(x+3)^2=3x+13+3x.

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Solution for (x+3)^2=3x+13+3x. equation: 



(x+3)^2=3x+13+3x.

We move all terms to the left:

(x+3)^2-(3x+13+3x.)=0

We add all the numbers together, and all the variables

(x+3)^2-(3x+3x.+13)=0

We get rid of parentheses

(x+3)^2-3x-3x.-13=0

We add all the numbers together, and all the variables

-3x+(x+3)^2-3x.-13=0

We move all terms containing x to the left, all other terms to the right

-3x+(x+3)^2-3x.=13

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